Wednesday, August 25, 2010

Variations of MSM-2


Initially, the S.E. “Grouping” Method seems to be difficult to grasp (or to understand). But the only tricky part is the creation of the sets of possible square roots


Rule 1: If the given problem ends with 225


1) N = 1, 3, 6 and 8

2) There are always two sets (or 2 groups), each having five (5) elements


Rule 2: If the given problem ends with 025


1) N = 4, 5 and 9

2) There are always two sets (or 2 groups), each having four (4) elements


Rule 3: If the given problem ends with 625


1) N = 2 and 7

2) There is always one set (or 1 group), having five (5) elements


Case No. 2


Given:


√66,341,025


Step 1:

(Left Column, 1st Row)


√66’34’10’25

... 8 ........... 5

N : 4, 5, 9


Step 2:

(Right Column, 1st Row)


P : 66’34

85 : 72’25 ↓

4↓ M : 0, 1, 2, 3, 4


Step 3:

(Left Column, 2nd Row)


1st Square Root Locator

.. 72’25

.. 68’06 \ ↓

.. 64..... /

.136’25 / 2

.. 68’12


Modify Step 2:


P : 66’34

85 : 72’25 ↓ /8250/

4↓ M : 0, 1, 2, 3, 4


Step 4:

List down the two sets of possible square roots

(Right Column, 2nd Row)


... ..............

8145 ......... 8245

8095 ......... 8195

8055 ......... 8155

8045 ......... 8145


Step 5:

(Left Column, 3rd Row)


2nd Sq. Rt. Locator

.. 68’06 \

.. 66’03 / ↑

.. 64 .....

.132’06 / 2

.. 66’03


Modify Step 4:

As an option, draw a square, enclosing the right set of possible square roots

(Right Column, 2nd Row)


8245 \ ↑

8195 /

8155 \

8145 / ↓


Step 6:

(Right Column, 3rd Row)


3rd Sq. Rt. Loc.

.. 68’06

.. 67’04 \ ↓

.. 66’03 /

.134’09 / 2

.. 67’04


Modify Step 4:

As option, cross out 8245 and 8195, leaving 8155 and 8145


8245 ← Eliminated

8195 ← Eliminated

8155

8145


Step 7:

(Left Column, 4th Row)


4th Sq. Rt. Loc.


↓ 8145 ........ 8155 ↑


.. 67’04

.. 66’53 \ ↓

.. 66’03 /

.133’07/ 2

.. 66’53


Step 8:

(Right Column, 4th Row)


Therefore:


√66,341,025 = 8,145


Case No. 3


Given:


√54,390,625


Step 1:

(Left Column, 1st Row)


√54’39’06’25

....7 ........... 5

N : 2, 7


Step 2:

(Right Column, 1st Row)


P : 54’39

75 : 56’25 ↓

4↓ M : 0, 1, 2, 3, 4



Step 3:

(Left Column, 2nd Row)


1st Square Root Locator

.. 56’25 \

.. 52’56 / ↑

.. 49 .....

.105’25 / 2

.. 52’62


Modify Step 2:


P : 54’39

75 : 56’25 ↓ /7250/

4↓ M : 0, 1, 2, 3, 4


Step 4:

List down the set of possible square roots

(Right Column, 2nd Row)


7475

7425

7375

7325

7275


We can re-group them as follows:


..

7475

7425

7375


..

7375

7325

7275


Step 5:

(Left Column, 3rd Row)


2nd Sq. Rt. Locator

.. 56’25

.. 54’40 \ ↓

.. 52’56 /

.108’81 / 2

.. 54’40


Modify Step 4:

The group with an up arrow is eliminated.

(As an optional, draw a square and enclose 7375, 7325, 7325)


7375

7325

7275


We can separate them into two groups:


..

7375

7325


..

7325

7275


Step 6:

(Right Column, 3rd Row)


3rd Sq. Rt. Loc.

.. 54’40 \

.. 53’48 / ↑

.. 52’56

.106’96/ 2

.. 53’48


7275 is eliminated


Step 7:

(Left Column, 4th Row)


4th Sq. Rt. Loc.


↓7325 ......... 7375↑


.. 54’40 \

.. 53’94 / ↑

.. 53’48

.107’88 / 2

.. 53’94


The ‘up arrow’ indicates that the ‘true’ square root is 7375


Step 8:

(Right Column, 4th Row)


Therefore:


√54,390,625 = 7,375

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